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First, solve for [ClX−] using the expression for Ksp and the given molarity for AgX+: Ksp=1.8×10−10=[AgX+][ClX−]. which rearranges to. ... <看更多>
#1. Solubility Product Constant (K sp ) Values at 25 o C
Salt K sp Salt K sp Salt K sp Bromides Bromides Carbonates Carbonates Oxalates Oxalates PbBr 2 6.6 x 10‑6 MgCO 3 6.8 x 10‑6 MgC 2 O 4 4.8 x 10‑6 CuBr 6.3 x 10‑9 NiCO 3 1.3 x 10‑7 FeC 2 O 4 2 x 10‑7
對於溶解平衡MmAn ⇌ mM n+ (aq) + nA m- (aq)，其溶度積Ksp = [c(M n+ )] m · [c(A m- )] n 。 例如，氯化銀（AgCl）的溶解平衡為：AgCl(s) ⇌ Ag + (aq) + Cl - (aq)，則Ksp ...
#3. Calculate Solubility of AgCl From Solubility Product - ThoughtCo
The solubility product of silver chloride (AgCl) is 1.6 x 10 -10 at 25 °C. The solubility product of barium fluoride (BaF2) is 2 x 10 -6 at 25 ...
Silver chloride is so insoluble in water (.0.002 g/L) that a saturated solution contains only about 1.3 x 10 -5 moles of AgCl per liter of water.
#5. Table of Solubility Product Constants (K sp at 25 o C)
AgCl, 1.8 x 10 -10. Chromates, BaCrO4, 2.0 x 10 -10. CaCrO4, 7.1 x 10 -4. PbCrO4, 1.8 x 10 -14. Ag2CrO4, 9.0 x 10 -12. Cyanides, Ni(CN)2, 3.0 x 10 -23.
#6. What is the K_(sp) for silver chloride? | Socratic
For which Ksp=[Ag+][Cl−]=??
#7. Solubility Product Constant (Ksp) | Chemistry for Non-Majors
As an example, silver chloride dissociates to a small extent into silver ions and chloride ions upon being added to water. text{AgCl}(s) rightleftarrows text{Ag} ...
#8. Solving K sp Problems: Part One - s 2 - chemteam.info
Example #1: Silver chloride, AgCl, has a Ksp = 1.77 x 10¯ 10. Calculate its solubility in moles per liter. Solution: 1) Write the dissociation equation:.
4) What is the molar concentration of [Ag+] in AgCl solution in 0.10 M NaCl ? (Ksp = 1.8 x 10-10) Remember that in this case the molar solubility of AgCl is ...
#10. Solubility Product Equilibria - Berkeley City College
Determine the solubility of AgCl (Ksp = 1.6 x 10. –10) in 0.010 M NaCl solution. 7. (a) Will precipitate of PbCl2 form when a 30.0-mL solution of 0.20 M ...
#11. The Ksp for AgCl is 1.8 x 10^-10. If NaCl is added to a 0.010 M ...
The Ksp for AgCl is 1.8 x 10^-10. If NaCl is added to a 0.010 M solution of AgNO3 in water, at... · Question: · Solubility Product Constant: · Answer and ...
#12. 沉澱(precipitation) | 科學Online - 國立臺灣大學
... 水溶液與氯化鉀(KCl)水溶液混合可產生氯化銀(AgCl)沉澱及硝酸鉀(KNO3) ... 的Ksp = 1.70×10-10，其值表示如下： Ag + (aq) +Cl – (aq)→ AgCl(s) Ksp ...
#13. Ag+(aq)+Cl-(aq) -> AgCl(s) 2) Solution or answer - Cal State LA
Solution or answer: AgCl(s) <==> Ag+(aq)+Cl-(aq) Ksp = 1.8 x 10-10 and. pKsp=-log(1.8 x 10-10)=9.74. 3) 1.66. Solution: @ equiv; #equivalents of Ag+ ...
#14. agcl ksp - 阿摩線上測驗
30.當Ag + 逐漸加入一個含[Br - ] = [Cl - ] = [CO3 2- ] = [AsO4 3- ] = 0.1M 的混合溶液，何者最先沉澱？ (A) AgBr (Ksp = 5.0 x 10 -13 ). (B) AgCl (Ksp = 1.8 x 10 -10 ).
#15. The solubility of AgCl Ksp = 1.2 x 10–10 in a 0.10 M NaCl ...
The solubility of AgCl Ksp = 1.2 x 10–10 in a 0.10 M NaCl solution is:a 0.1 M b 1.2 x 10–6 Mc 1.2 x 10–9 M d 1.2 x 10–10 M.
#16. Re: [高中] ksp 沉澱問題- 看板Chemistry - 批踢踢實業坊
引述《evanzxcv (高密度聚乙烯)》之銘言： : ※ 引述《appl (彰)》之銘言： : : 已知ksp: AgCl=10^-10 AgBr=10^-12 AgI=10^-16 : : 現有1L 0.1M NaCl ...
#17. CHEM 36
1. Silver can form a precipitate by reaction with chloride (AgCl; Ksp = 1.6 x 10-10) and with chromate (Ag2CrO4; Ksp = ...
#18. What is the molar solubility of AgCl (Ksp = 1.80 × 10⁻¹⁰) in ...
What is the molar solubility of AgCl (Ksp = 1.80 × 10⁻¹⁰) in 0.560 M NH₃? (Kf of Ag(NH₃)₂⁺ is 1.7 × 10⁷). Follow • 2. Add comment. More.
#19. The Ksp of AgCl at 25 C is 1.6*10 - Wyzant
The Ksp of AgCl at 25 C is 1.6*10^-10. Consider a solution that is 1*10^-6 M CaCl2 and 1*10^-5 M AgNO3. The answer is Q < Ksp and a ...
#20. Solved What is the molar solubility of AgCl (Ksp = 1.80 - Chegg
Question: What is the molar solubility of AgCl (Ksp = 1.80 × 10⁻¹⁰) in 0.980 M NH₃? (Kf of Ag(NH₃)₂⁺ is 1 × 10⁷). This problem has been solved! See the answer ...
#21. The solubility (in mol L-1) of AgCl (Ksp =1.0 × 10-10) in a
AIEEE 2012: The solubility (in mol L-1) of AgCl (Ksp =1.0 × 10-10) in a 0.1 M KCl solution will be (A) 1.0 × 10-9 (B) 1.0 × 10-10 (C) 1.0 × 10-5.
#22. the ksp for agcl is 18 x 1010 what is the molar solubility of agcl ...
the ksp for agcl is 18 x 1010 what is the molar solubility of agcl in pure water - Chemistry - TopperLearning.com | xv8ygu7.
#23. 35. The solubility product of AgCl is Rsp. Then the ... - Instasolv
Then the solubility of AgCl in x M KCl is х (1) Ksp x x² (2) Ksp SP 2014. NEET. Chemistry. Solution.
#24. Ch 15 Solubility Equil Ksp Practice III - key.pdf
Ch.15.6: Solubility Equilibria & Solubility Product Constant Ksp - Practice III ... 13) In which of the following aqueous solutions would you expect AgCl to ...
#25. The solubility of AgCl (Ksp = 1.2 x 10^–10) in a 0.10 M NaCl ...
Correct option: (c) 1.2 x 10 –9 M. Explanation: Ksp AgCl = 1.2 x 10 –10 = [Ag + ] [Cl – ] = [s][s + 0.1]. where s is solubility of AgCl.
#26. Chemistry 192 Problem Set 6 Spring, 2018 Solutions
The solubility product of AgCl is Ksp = 1.1 × 10−10. Calculate the weight of silver nitrate that must be added to 10. mL of a 0.10 M sodium chloride ...
#27. Solubility of KHT and Common ion Effect
The molar solubility is the solubility of the compound in moles per liter. Example: Dissociation of Silver Chloride. AgCl (s) ⇔ Ag+ (aq) + Cl- (aq). Ksp = [ ...
#28. 15.1: Precipitation and Dissolution - Chemistry LibreTexts
... soluble ionic solid is called the solubility product, Ksp, of the solid. ... However, when we add an excess of solid AgCl to water, ...
#29. Calculate the molar solubility of AgCl (Ks... | Clutch Prep
Problem: Calculate the molar solubility of AgCl (Ksp = 1.8 × 10–10 at 25°C) in ... Since the AgCl ionic, it will form ions when dissociating in a solution.
#30. 百度知道
固体溶解度尚未有广泛适用的公式描述。 Ksp被定义为下面的溶解反应的平衡常数， AgCl = Ag+ + Cl- 由于AgCl是难溶的固体，活 ...
#31. SOLUBILITY PRODUCT In a saturated solution of a salt, there ...
s = [Ksp]1/2 ……….(11). The solubility product of AgCl at a given temp is determined by adding AgCl in a solution of KCl of a known concentration say b moles ...
#32. 莫尔法_搜狗百科
已知Ksp（AgCl）=1.8x10-10，Ksp（Ag2CrO4）=1.2x10-12，Ksp（AgCl）>Ksp（Ag2CrO4），按照分部沉淀原理则应是铬酸银先析出，与实际情况不符。实际上，AgCl是AB型难溶 ...
#33. Answer to Question #135002 in General Chemistry for hi
what is The Ksp of AgCl at 25 oc is 1.0x10-10. Calculate the concentration of Ag+ and Cl- ions in a saturated solution of AgCl, ...
#34. 什麼是溶度積ksp - 我說的天地的部落格
以AgCl為例，儘管AgCl在水中溶解度很小，但並不是完全不溶解。 從固體溶解平衡角度認識：AgCl在溶液中存在下屬兩個過程：. ①在水 ...
#35. Solubility Product Constants, Ksp - Wired Chemist
Solubility Product Constants, Ksp. ... AgCl, 1.8 x 10 -10. PbCl2, 1.0 x 10 -4. Hg2Cl2, 2.0 x 10 -18. Cyanides. Hg2(CN)2, 5 x 10 -40. AgCN, 1.6 x 10 -14 ...
#36. kvx594-Chemistry and Physics-Tom-Rybolt - University of ...
Dr. Thomas R. Rybolt has been a member of the faculty at UTC from 1981 to the present, and has served as Department Head from 2010 to 2016.
#37. Calculate the solubility of AgCl in: Ksp = 1.6x10^-10 a) 100 ml ...
Questions. chemistry. Calculate the solubility of AgCl in: Ksp = 1.6x10^-10 a) 100 ml of 4.00 x 10^-3 M Calcium chloride
#38. Solubility Equilibria
Calculate the molar solubility of AgCl [Ksp = 1.8 x 10-10] in: a. distilled water and b. 0.100 M NH3 [Kf = 1.6 x 10+7 for Ag(NH3)2+]. 2 (a). AgCl(s).
#39. Solubility Equilibria A. Ksp, the Solubility Product Constant ...
C. Finding the Solubility from Ksp. (Section 17.1). 1. Example: Calculate the molar solubility of AgCl and the concentrations [Ag.
#40. CHEMISTRY 1220 - Chapter 1
AgCl. Ksp = 1.6 x 10-‐10. Ag2CO3. Ksp = 8.1 x 10-‐12. AgBr. Ksp = 5.0 x 10-‐13. Calculate the molar concentration of silver ion for each of the salts.
#41. Ksp of AgCl is . Its solubility in 0.1 M KNO3 will be - Vedantu
Complete step by step answer: -Firstly, let us talk about the solubility product constant (K$_{sp}$). It tells us that the solid AgCl when in equilibrium with ...
#42. The solubility product of `AgCl` is `1.8xx10 - YouTube
#43. Solubility Product Constant
Suppose the solubility of silver chloride, AgCl, is 1.9 x 10-3 g/L. Calculate its Ksp. 1.9 x 10-3 grams AgCl ( 1 mole AgCl. 143.4 grams AgCl. ) = 1.33x10.
#44. Finding the Equilibrium Constant for a New Reaction
AgCl (s). Ag+(aq) + Cl–(aq). Ksp = [Ag+][Cl–]=1.8 × 10−10 where Ksp is the solubility product; acid dissociation reactions. CH3COOH(aq) + H2O(l).
#45. CHEM EXAM#2 Flashcards | Quizlet
Rank the following salts in order of increasing molar solubility. Salt Ksp BaSO4 1.1 × 10-10 AgCl 1.8 × 10-10 BaCO3 9.1 × 10-9 CdS 8 × 10- ...
#46. What is the molar solubility of AgCl in 1 M NH3? The Ksp for ...
Hence, [Ag(NH3)2+] = C , and [Ag+] = Ksp/[Cl-] ... ... of AgCl in 1 M NH3? The Ksp for AgCl is 1.6 x 10^-10 and the Kf for Ag(NH3) 2+= 1,5*10^7. 1 Answer.
#47. What is the maximum solubility of AgCl (ksp=1.8x10^-10) in an ...
Get an answer for 'What is the maximum solubility of AgCl (ksp=1.8x10^-10) in an HCl solution of pH=2.8 ? The maximum solubility of AgCl in pure water is ...
#48. CHEM1612 2007-N-11 November 2007 • The solubility ...
The solubility product constant of AgCl is Ksp = 1.8 × 10–10 M2. Using the relevant electrode potentials found on the data page, ...
#49. Today Complex Equilibria Approximations when do your ...
The Ksp for AgCl is much smaller so we can selectively precipitate the AgCl. Page 10. Principles of Chemistry II. © Vanden Bout. I have a solution which ...
#50. c. Write the solubility equation for the precipitate formed above ...
Ksp and Solubility ... AgNO3(aq) + NaCl(aq) → AgCl(s) + NaNO3(aq) ... Calculate the Ksp for Bi(OH)3 if 1.1 x 10-8 moles of Bi(OH)3 dissolve in 1.0.
#51. Amount of Cl- needed to precipitate AgCl given Ksp and [Ag+]
First, solve for [ClX−] using the expression for Ksp and the given molarity for AgX+: Ksp=1.8×10−10=[AgX+][ClX−]. which rearranges to.
#52. What is the solubility of AgCl (Ksp = 1.6 x 10-10) in 5.7 x 10-1 ...
Jean M. Chemistry 101. 6 months ago. What is the solubility of AgCl (Ksp = 1.6 x 10-10) in 5.7 x 10-1 M NaCl?
#53. Chemistry 12 Tutorial 10 Ksp Calculations
So, we find that the Ksp for AgCl = 1.8 x 10-10. The net-ionic equation for the substance, AgCl dissolving in water is: -s. AgCl(s).
#54. the solubility product of agcl is ksp. than the ... - Brainly.in
The solubility product of agcl is ksp. than the solubility of agcl in xm kcl is - 5418421.
#55. F. Ksp calculations What is the molar solubility of AgCl given ...
FREE Answer to F. Ksp calculations What is the molar solubility of AgCl given that the Ksp of AgCl...
#56. Ksp of AgCl is 1.8 × 10−10. Calculate molar solubility in 1 M ...
Ksp of AgCl is 1.8 × 10−10. Calculate molar solubility in 1 M AgNO3. ... \[\ce{AgCl_{(s)} ⇌ Ag^+_{( aq)} + Cl^-_{( aq)}}\].
#57. Solubility
Since the concentration of Ag + (or Cl - ) in the solution must match the amount of AgCl dissociated then the solubility of of silver chloride in water is 1.7 x 10 ...
#58. What is the KSP expression for AgCl? - Best Acting Colleges ...
How do you know the KSP of AgCl? Which is the product solubility constant of AgCl? What is the K _ ( sp ) for silver chloride? Why is the polarising power ...
#59. Ch 16 Ksp Practice Test
Ch 16 Ksp Precipitation Reactions. PRACTICE TEST ... Ksp = 1.8 x 10-147 Pbarové b aroy ... Calculate the molar solubility of AgCl in a.
#60. Answered: 25ºC, AgCl (Ksp = 1.6 x 10-10) is less… | bartleby
Solution for 25ºC, AgCl (Ksp = 1.6 x 10-10) is less soluble as compared to PbCl2(Ksp = 2.4 x 10-4) True or false?
#61. What is the molar solubility of AgCl (Ksp = 1.80 x 10 - ITProSpt
What is the molar solubility of AgCl (Ksp = 1.80 x 10-10). What is the equilibrium constant for the solubility of FeCO3 (Ksp = 2.1 x 10. What is the molar ...
#62. Ksp
Calculate Ksp for, AgCl. 2) Calculate the molar solubility of barium sulfate, BaSO4, in pure water and the concentration ...
#63. Chapter 17 Lecture- Buffers & Ksp - SlideShare
The term slightly soluble is more accurate because with very low concentrations of Ag+ and Cl- there is no AgCl(s) formed. Equilibrium calculations allow us ...
#64. In 1 L saturated solution of AgCl(Ksp AgCl = 1.6 * 10-10), 0.1 ...
In 1 L saturated solution of AgCl(Ksp AgCl = 1.6 * 10-10), 0.1 mol of CuCl (Ksp CuCl = 1.0 * 10-6) is added. The resultant concentration of Ag+ in the ...
#65. Exercise 10 SOLUBILITY PRODUCT CONSTANTS
sodium chloride solution are mixed, silver chloride crystals AgCl (a precipitate) ... This equilibrium constant Ksp is called a solubility-product constant.
#66. How to Calculate Molar Solubility From KSP? - Sciencing
Since there is no concentration for the solid AgCl, this can be removed from the equation. The resulting K value is called Ksp or the solubility ...
#67. The Ksp of Ag2CrO4, AgCl, AgBr and AgI are respectively, 1.1 ...
Which one of the following salts will precipitate last if AgNO3 solution is added to the solution containing equal moles of NaCl, NaBr, NaI and Na2CrO4? AgI.
#68. In 1 L saturated solution of AgCl [Ksp(AgCl) = 1.6 × 10^−10 ...
In 1 L saturated solution of AgCl [Ksp(AgCl) = 1.6 × 10^−10] 0.1 mol of CuCl [Ksp(CuCl) = 1.0 × 10^−6] is added.
#69. In 1 L saturated solution of AgCl [Ksp(AgCl) = 1.6 ´ 10 - M4maths
IIT-JEE Question Solution - In 1 L saturated solution of AgCl [Ksp(AgCl) = 1.6 ´ 10^-10], 0.1 mol of CuCl [Ksp(CuCl) = 1.0 ´ 10^-6] is added.
#70. The Ksp of AgCl at 298 K is 1 × 10-10. Calculate electrode ...
The Ksp of AgCl at 298 K is 1 × 10-10. Calculate electrode potential of Ag electrode immersed in 1 M KCl soln.. [Given: E0 Ag+/Ag = 0.799 V ]electrode ...
#71. 为什么碘化银KSP大于氯化银 | 健康跟著走
氯化銀ksp - 氯化银的沉淀溶解平衡如下：AgCl(s)⇋Ag++Cl-K2=Ksp(AgCl)（2）加入碘化钾,氯化银是否能转化为碘化银沉淀,主要看AgCl(s)+I-⇋A...
#72. The solubility product of AgCl is Ksp Then the ... - Meritnation
The solubility product of AgCl is Ksp. Then the solubility of AgCl in xM KCl is 1.Ksp×x2 2.x/Ksp 3.Ksp/x2 4.Ksp/x. Share with your friends.
#73. Solubility and complex ion formation (video) | Khan Academy
#74. Determining Ksp(AgCl) through the Formal Potential of the Ag
calculate Ksp of AgCl using the experimentally determine E. 0 ′s. The experimental technique to be employed is called potentiometry .
#75. In 1 L saturated solution of AgCl [K sp (AgCl) = 1.6 x 10
Dec 21,2021 - In 1 L saturated solution of AgCl [Ksp(AgCl) = 1.6 x 10-10], 0.1 mol of CuCl [Ksp(CuCl) = 1.0 x 10-6] isadded. The resultant concentration of ...
#76. 塩の溶解度 7-1. AgCI(s) → Ag +(aq) + Cl-(aq) Ksp = [Ag+][Cl ...
1.00x10-4 mol の AgCl が沈殿したとすると、1.00x10-5 mol の Ag+イオンが液中に残る。 これより、一部の AgCl は溶解している。 [Ag+] = 5.O x 10-6 + x. [Cl-] = x.
#77. AgCl과 Ag2CrO4의 용해도 - 좋은 습관 - 티스토리
g/L 단위에서 용해도가 더 큰 것은 무엇인가? A) Which has the greater molar solubility: AgCl with Ksp = 1.8×10^-10 ...
#78. สมดุลของการละลาย (Solubility Equilibria)) - Web Hosting RMUTP
จากสมการ (1.2) สมการค่าคงที่สมดุลของการละลาย คือผลคูณของไอออนยกก้าลังด้วย. สัมประสิทธิ์จ้านวนโมลของสมการการแตกตัว ตัวอย่างข้างต้นเป็นการเขียน Ksp ของ AgCl ที่ ...
#79. Foundations of College Chemistry, Alternate
The solubility of in water is at 25°C. The equation for the equilibrium between and its ions in solution is AgCl 1.3 * 10-5 mol>L AgCl Ksp, Ksp solubility ...
#80. √ Kelarutan dan Hasil Kali Kelarutan [Lengkap + Contoh Soal]
Hasil Kali Kelarutan (Ksp). Ketika garam yang sukar larut seperti perak klorida (AgCl) dilarutkan dalam air, maka pada kondisi tepat jenuh ...
#81. 無題
Ksp lab ap chemistry. ... Given that the solubility product constant, Ksp, for AgCl is 1. 2. ap chemistry! Below you will find Important Course Documents ...
#82. Agcl | Sigma-Aldrich
agcl · [(IPr)AgCl] · Ag/AgCl (3M KCl) Reference Electrode · Ag/AgCl (3M NaCl) Reference Electrode · Silver chloride · Potassium chloride solution.
#83. Oswaal CBSE Question Bank Class 11 For Term-I & II Chemistry ...
In one litre saturated solution of AgCl [ Ksp 1.6 x 10-10 ) , 0.1 mol of CuCl [ Ksp = 1.0 x 10-6 is added . Find out the resultant concentration of Ag + in ...
#84. Chemistry: Principles and Reactions - 第 397 頁 - Google 圖書結果
From Table 15.2, it appears that BaCO3 (Ksp 5 2.6 3 1029) is less soluble than MgCO3 (Ksp 5 ... Substitute into the Ksp expression for AgCl and find [Ag1].
#85. Principles of Chemical Sensors - 第 111 頁 - Google 圖書結果
... Ksp ( AgCl ) / Ksp ( AgX ) > ac / ax ( 4-49 ) the electrode will undergo metathesis and its surface will become partially covered with the solid phase ...
#86. Hitunglah kelarutan dari garam perak berikut AgCl ...
Hitunglah kelarutan dari garam perak berikut AgCl (Ksp=1010) ...
#87. 17.2: Molar Solubility and Ksp - Newsstellar
In the case of a simple 1:1 solid such as AgCl, this would just be the concentration of Ag + or Cl – in the saturated solution. But for a more complicated ...
#88. What is the product of consecutive stability constants? - Knotius
Complex Ion Equilibria - Stepwise Formation Constant Kf & Ksp Molar ... For AgCl units would be M2 or mol2 dm-6, and for Gd2(SO4)3 M5 or mol5 dm-10.
agcl ksp= 在 Re: [高中] ksp 沉澱問題- 看板Chemistry - 批踢踢實業坊 的推薦與評價
※ 引述《evanzxcv (高密度聚乙烯)》之銘言：
: ※ 引述《appl (彰)》之銘言：
: : 已知ksp: AgCl=10^-10 AgBr=10^-12 AgI=10^-16
: : 現有1L 0.1M NaCl 0.1M NaBr 0.1M NaI混合溶液
: : 慢慢加入0.2mole AgNO3
: : 1.請問總共有哪些沉澱?
: : 2.各離子濃度??
: 借題來練功一下好了XD 我也是將近四年沒碰分析化學 ><
: 首先AgI最難溶,所以先把他通通沉澱光
: 剩下0.2-0.1=0.1mol Ag+, 亦即0.1M Ag+
: 還剩下多餘的Ag+可以跟Br-沉澱,AgBr次難溶,也給他沉澱光,
: 溶液中就沒有Ag+了,剩下0.1M的Cl-
: 然而AgI、AgBr並不是完全不溶,還會照Ksp解離出來一點,
: 解離出來Ag+的來源有AgBr跟AgI兩者,故[Ag+]=[Br-]+[I-] (Cl-晚點再回來處理)
: 兩個式子兩個未知數,設[Br-]=x,[I-]=y,則[Ag+]=x+y,解一下聯立方程式:
: (x+y)x=10^-12
: (x+y)y=10^-16
: 兩式相除得x=10000y,代入第二條,10001y^2=10^-16,
: 解得y=1.00*10^-10, x=1.00*10^-6,
: 亦即[Ag+]=x+y=1.00*10^-6M
: 表示由AgBr跟AgI解離回去的Ag+還有這麼多,而目前Cl-還是0.1M的狀態,
: 所以乘起來看看AgCl會不會有沉澱:
: [Ag+][Cl-]=(1.00*10^-6)(0.1)=1.00*10^-7大於AgCl的Ksp,
: 所以得到結論AgCl也會沉澱,亦即:AgCl、AgBr、AgI都會沉澱!
: 至於會沉澱多少呢?三條式子,三個未知數,來解個聯立方程式吧:
: 首先做點假設,因為根本沒多少Ag+跟Cl-沉澱,所以[Cl-]約略等於0.1M.
: 因為知道Cl-的濃度,所以可以把[Ag+]給秒殺:
: [Ag+][Cl-]=[Ag+]*0.1=10^-10,得[Ag+]=1.00*10^-9.
: 接下來[Br-]跟[I-]就一樣簡單,
: [Ag+][Br-]=(1.00*10^-9)*[Br-]=10^-12,得[Br-]=1.00*10^-3.
: [Ag+][I-]=(1.00*10^-9)*[I-]=10^-16,得[I-]=1.00*10^-7.
: 所以所有離子濃度分別為:
: [Ag+]=1.00*10^-9M
: [Cl-]=0.100M
: [Br-]=1.00*10^-3M
: [I-]=1.00*10^-7M
: (不知道原題目有效數字幾位,自己取一下正確的有效位數吧 XD)
: 總之Ksp可以視為一種平衡常數,跟酸解離的Ka一樣,
: 酸鹼滴定是從最酸的Ka1開始依序中和,沉澱同樣道理也是從Ksp最小開始依序沉澱,
: 然後因為這題先用依序沉澱法做出來還有一大堆的Cl-,
: 變成Cl-的濃度主導了Ag+的濃度,然後再反回去算出Br-跟I-濃度即可.
不好意思
我的想法跟e大的不太一樣
想請大家一起來討論一下QQ"
先謝謝囉^^"
先寫下了[Ag+]=0.2M
[Cl-]=0.1M Ksp=10^-10
[Br-]=0.1M Ksp=10^-12
[I-] =0.1M Ksp=10^-16
隨後依序對I- → Br- → Cl- 下手
AgI = Ag+ + I-
0 0.2 0.1
0.1 0.1 0 ←先平移
↓
AgBr = Ag+ + Br-
0 0.1 0.1
0.1 0 0 ←先平移
0.1-x +x +x →難溶塩解離 → x = 10^-6M =[Ag+]
↓
AgCl = Ag+ + Cl-
0 10^-6 0.1 ←呀呀! 會沉澱qq"
10^-6 0 0.1-(10^-6) ←先平移
(10^-6)-z +z 0.1-(10^-6)+z →再解離 → 計算得 z = 10^-9 M =[Ag+]
再用最後的[Ag+]=10^-9 反推回[Br-] [I-]的濃度
可得 [Br-] = 10^-3 M
[I- ] = 10^-7 M
答案跟e大的一樣
這種過程我想高中應該會給分
可是...
不知道大學考試這樣寫會不會有問題存在?
請大家幫忙指證一下囉
謝謝^^
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